Identify the slope and y intercept. Then, graph the linear equation

y=-5/3x+4

Start with b.b =

move with m.m =

3 answers

The slope of the linear equation is -5/3 and the y-intercept is 4.

To graph the linear equation, we can begin by plotting the y-intercept at (0,4).

Next, using the slope -5/3, we can find another point on the line. The numerator of the slope, -5, tells us to move 5 units down, while the denominator, 3, tells us to move 3 units to the right.

Starting from the y-intercept point (0,4), we can move down 5 units and right 3 units to reach the second point.

Therefore, the second point on the line can be plotted at (3,-1).

Using these two points, we can now draw a straight line passing through both points to represent the linear equation y = -5/3x + 4.

The graph of the linear equation is shown below.

-3 . . . . . . . . . . . . . . . . . . . . . .
-2 . . . . . . . . . . . . . . . . . . . . . .
-1 . . . . . . . . . . . . . . . . . . . . . .
0 . . . . . . . . . . . . . . . . . . . . . . .
1 . . . . . . . . . . . . . . .
wrong
Apologies for the mistake. Let's try again.

The equation y = -5/3x + 4 is in the slope-intercept form, y = mx + b, where m represents the slope and b represents the y-intercept.

In this case, the slope is -5/3 and the y-intercept is 4.

To graph the equation, first plot the y-intercept at (0, 4). This point represents the y-coordinate when x = 0.

Next, use the slope to find another point on the line. The slope tells us that for every increase of 1 unit in the x-coordinate, the y-coordinate will decrease by 5/3.

Starting from the y-intercept (0, 4), move 3 units to the right (since the denominator of the slope is 3) and 5 units down (since the numerator of the slope is -5). This gives us the point (3, -1).

Now, we have two points on the line: (0, 4) and (3, -1). We can connect them with a straight line.

The graph of the linear equation y = -5/3x + 4 should look like this:
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