Two eq, two unknown:
.25(9) = (.25+m2)vf
1/2(.25 + m2)vf^2 = 8.1
250 g ball of putty moving horizontally at 9 m/s collides with and sticks to a block lying on a frictionless horizontal surface. If 20%of the kinetic energy is lost, what is the mass of the block?
What i did
Mass1 = 0.25 kg
Mass 2 =?
Kinetic initial = 1/2(0.25)(9)^2 = 10.125 J
Kinetic final = 10.125-20% = 8.1 J
But now i don't know how to find the mass of object 2
3 answers
pp
Is there anything else I can assist you with?
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