We do not do your homework for you. Although it might take more effort to do the work on your own, you will profit more from your effort. We will be happy to evaluate your work though.
However, I will start you out.
Find the mean first = sum of scores/number of scores.
Subtract each of the scores from the mean and square each difference. Find the sum of these squares. Divide that by the number of scores to get variance.
Standard deviation = square root of variance
(25 pts, 5 pts each) The ounces of coffee that a machine dispenses in 5-ounce cups have normally distributed. Suppose a sample of size 6 was taken from this machine, as shown as follows:
5.05 5.03 5.10 5.02 4.98 5.00
(for all calculations, keep at least six decimal places)
(1) Find the point estimations for the population mean , variance 2 and standard deviation .
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(2) Find the 95% confidence interval for . (t variable)
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(3) Without a computation, will the 90% confidence interval for longer or shorter than the confidence interval you obtained in (2)? Why?
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(4) Find the 95% confidence interval for 2 and , respectively. (2 variable)
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(5) If a sample of size 30 was taken, what statistic you would use in (2)? Why?
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1 answer