The neutralization equation is
HCl + NaOH ==> NaCl + H2O
0.005 mole HCl will require 0.005 mol NaOH.
25 ml HCl x 1L/1000mL x .200HCl/1L = .005 mol HCl.
Using the balanced equation from this, how many moles of NaOh will you need to completely neutralize the HCl?
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