To find the slope of a line parallel to 2x - y = 16, we first need to rewrite the equation in slope-intercept form (y = mx + b), where m is the slope of the line.
2x - y = 16
-y = -2x + 16
y = 2x - 16
Now we can see that the slope of the line is 2.
Since parallel lines have the same slope, the slope of a line parallel to 2x - y = 16 is also 2.
25.
Find the slope of a line parallel to 2x-y= 16
3 answers
26.
Which is the equation of the line with slope 5 that contains point (−2, −3)?
y + 3 = 5(x + 2)
y – 2 = 5(x – 3)
y – 3 = 5(x – 2)
y + 2 = 5(x – 3)
Which is the equation of the line with slope 5 that contains point (−2, −3)?
y + 3 = 5(x + 2)
y – 2 = 5(x – 3)
y – 3 = 5(x – 2)
y + 2 = 5(x – 3)
To find the equation of a line with a slope of 5 that contains the point (-2, -3), we can use the point-slope form of the equation of a line: y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope.
Substitute the given point (-2, -3) and the slope 5 into the point-slope form:
y - (-3) = 5(x - (-2))
y + 3 = 5(x + 2)
Therefore, the correct equation of the line with slope 5 that contains the point (-2, -3) is y + 3 = 5(x + 2).
So, the correct answer is: y + 3 = 5(x + 2)
Substitute the given point (-2, -3) and the slope 5 into the point-slope form:
y - (-3) = 5(x - (-2))
y + 3 = 5(x + 2)
Therefore, the correct equation of the line with slope 5 that contains the point (-2, -3) is y + 3 = 5(x + 2).
So, the correct answer is: y + 3 = 5(x + 2)