25.00 mL of a solution of HCL was titrated with 0.4500 M NaOH using the indicator bromthymol blue. Successice readings of the burette gave the following data: colour:

Question

Volume of NaOH (mL)= i.) 16.35 yellow
ii.) 16.40 yellow
iii.) 16.45 green
iv.) 16.50 blue
Based on the data, the original [HCL] is...

Answer 1

I would average the readings of the base, then mL acid x M acid = mL base x M base. Then round to 4 significant figures.