5(2m+3)-(1-2m)=2[3(3+2m)-(3-m)]

How far did you get?

Start with
10m +15 -1 +2m = 2[9 + 6m -3 +m]
12m +14 = 2[7m +6] = 14m +12

Yes, it has a solution.
Finish the job.

Thanks

Did you get m=1?

To solve this equation, let's simplify the expression step by step.

First, let's distribute the terms on both sides of the equation:

5(2m+3) - (1-2m) = 2[3(3+2m) - (3-m)]

Simplifying each side:

10m + 15 - 1 + 2m = 6(3 + 2m) - 2(3 - m)

Combining like terms:

12m + 14 = 18 + 12m - 6 + 2m

Now, let's simplify further by combining like terms on both sides:

12m + 14 = 12m + 12m + 18 - 6 + 2m

12m + 14 = 24m + 12

Next, let's isolate the variable by moving the constant terms to one side and the variable terms to the other side:

12m - 24m = 12 - 14

-12m = -2

Finally, divide both sides of the equation by -12 to solve for m:

m = -2 / -12
m = 1/6

Therefore, the solution to the equation is m = 1/6.

To solve the equation, I simplified each side separately by distributing, combining like terms, and isolating the variable on one side of the equation.