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I am trying to write this rational expression in its simplest form:

2-x+2x^2-x^3/x^2-4

However I have no idea how to factor the four numbers on the top. I"m used to factoring just three numbers. Can you show me how to do this? Thanks!!!
16 years ago

Answers

Reiny
use grouping
2-x+2x^2-x^3
= (2-x) + x^2(2-x)
= (2-x)(1+x^2)

so
(2-x+2x^2-x^3)/(x^2-4)
= (2-x)(1+x^2)/[(x-2)(x+2)]
= -(1+x^2)/(x+2)
16 years ago
Shavaleir
2x+4x-3x/2x-4=
6x-3x/2x-4= 5/10x
16 years ago

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