if 10 mol of hydrogen reacted with oxygen, what volume of liquid water could be produced?

Answer 1

2H2 + O2 ==> 2H2O
Assuming the 10 moles H2 had all the oxygen needed to react completely, then 10 moles H2 x (2 moles H2O/2 moles H2) = 10 moles H2 x 2/2 = 10 x 1/1 = 10 moles H2O? 10 moles x 18.015 g/mol = 180.15 grams. If we use the density of water as 1.00 g/mL, then 180.15 g H2O = ?? mL.Check me out on that.

Answer 2

I am not sure I need help. thanks.