Question

5 of 55 of 5 Items Question Jerrica is packing a box that can hold at most 65 pounds. She starts by putting a container in the box that weighs 26 pounds. She plans to fill the rest of the box with books. Each book she places in the box weighs 1.3 pounds. Write an inequality for the number of books Jerrica can put in the box, and describe the solutions.(2 points) x+ ≤, where x is the number of books Jerrica can put in the box. Jerrica can put at most books in the box.

Answer 1

there suppose to b a number on the first blank its not x and on the last blank its wrong

Answer 2

last one is not right

Answer 3

about how many books can go in the box

Answer 4

x+26 ≤ 65, where x is the number of books Jerrica can put in the box. Jerrica can put at most 35 books in the box.

Answer 5

Apologies for the confusion. The correct inequality would be:

1.3x + 26 ≤ 65, where x is the number of books Jerrica can put in the box.

The solutions to this inequality represent the number of books that Jerrica can put in the box. In this case, the number of books must satisfy the condition that when each book (weighing 1.3 pounds) is added to the weight of the container (26 pounds), the total weight does not exceed 65 pounds, which is the maximum weight capacity of the box.

Answer 6

Apologies for the error. The correct inequality is:

1.3x + 26 ≤ 65, where x is the number of books Jerrica can put in the box.

The solutions to this inequality represent the number of books that Jerrica can put in the box. In this case, the number of books must satisfy the condition that when each book (weighing 1.3 pounds) is added to the weight of the container (26 pounds), the total weight does not exceed 65 pounds, which is the maximum weight capacity of the box.

Answer 7

To determine the number of books that can go in the box, we can solve the inequality:

1.3x + 26 ≤ 65

Subtract 26 from both sides:

1.3x ≤ 65 - 26

1.3x ≤ 39

Now divide both sides by 1.3:

x ≤ 39 / 1.3

x ≤ 30

So, Jerrica can put at most 30 books in the box.