Asked by Anna
Determine the enthalpy for the partial combustion of methane to carbon monoxide-
2CH4(g) + 3O2(g) = 2CO(g) + 4H2O(l) from
change in enthalpy (CH4,g) = -890. kJ mol-1 and
change in enthalpy (CO,g) = -283.0 kJ mol-1
2CH4(g) + 3O2(g) = 2CO(g) + 4H2O(l) from
change in enthalpy (CH4,g) = -890. kJ mol-1 and
change in enthalpy (CO,g) = -283.0 kJ mol-1
Answers
Answered by
DrBob222
delta H rxn = (delta H products-delta H reactants). You will need to look up the delta H for H2O unless you have it and didn't post it.
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