The given system of equations can be written as:
2x - 3y = -10 ----(1)
-2x + 4y = 14 ----(2)
To solve the system, we can use the elimination method by adding the equations (1) and (2):
(2x - 3y) + (-2x + 4y) = (-10) + 14
x + y = 4 ----(3)
Now, let's multiply equation (3) by -2 and add it to equation (1):
-2(x + y) + (2x - 3y) = -2(4) + (-10)
-2x - 2y + 2x - 3y = -8 - 10
-5y = -18
y = (-18) / (-5)
y = 18/5
y = 3.6
Substitute the value of y in equation (3):
x + 3.6 = 4
x = 4 - 3.6
x = 0.4
Therefore, the solution to the system of equations is x = 0.4 and y = 3.6.
Hence, there is exactly 1 solution to the given system of equations.
`2x-3y=-10`
`-2x+4y=14`
How many solutions are there?
1
No Solution
Infinitely Many Solutions
1 answer