Asked by Joanne
how can i solve this problem? The number of tickets sold each day for a upcoming peformance of Handel's Messiah is given by N(x)=0.4x^2+8x+11, where x us the number of days since the concert was first announced. When will daily ticket sales peak and how many tickets will be sold that day.
Answers
Answered by
Ms. Sue
Your <u>School Subject</u> is <b>Math</b>, not "college."
Answered by
Reiny
since you labeled it "college" I will assume you know Calculus.
N(x)=0.4x^2+8x+11
N'(x) = .8x + 8
= 0 for a max/min of N
.8x + 8 = 0
x will be a negative, so your problem makes no sense.
your function is an upwards parabola so it has a minimum, not a maximum.
perhaps you have a typo and the first term is -.8x^2
then the above result becomes
-.8x + 8 = 0
x = 10
and N(10) = -.8(100) + 80 + 11
= 11
11 tickets sold ????
There are more people singing Hallelujah.
N(x)=0.4x^2+8x+11
N'(x) = .8x + 8
= 0 for a max/min of N
.8x + 8 = 0
x will be a negative, so your problem makes no sense.
your function is an upwards parabola so it has a minimum, not a maximum.
perhaps you have a typo and the first term is -.8x^2
then the above result becomes
-.8x + 8 = 0
x = 10
and N(10) = -.8(100) + 80 + 11
= 11
11 tickets sold ????
There are more people singing Hallelujah.
Answered by
jim
Apart from the subject, that equation isn't going to peak for x > 0. I think you may have an error in the question.
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