To find the standard form of the quadratic expression, we need to simplify the given expression and collect like terms.
The given expression is: (4x - 2)(6)(2x + 7)
Using the distributive property, we can expand this expression:
= (4x - 2)(6)(2x + 7)
= 24x(2x + 7) - 12(2x + 7)
= 48x^2 + 168x - 24x - 84
Collecting like terms, we have:
= 48x^2 + (168x - 24x) - 84
= 48x^2 + 144x - 84
So, in standard form, the expression is: 48x^2 + 144x - 84
The coefficient of the x^2 term is 48, the coefficient of the x term is 144, and the constant term is -84.
Write the expression (4x-2)•6(2x+7) in standard form of a quadratic expression, ax^2 +bx +c. What are the values of the coefficients of each and the constant term?
1 answer