Let's say the regular price of each ticket is p dollars.
The total cost of the tickets without any discount is 6p dollars.
According to the information given, Dea buys the tickets for $1.50 off the regular price, so each ticket costs (p - $1.50).
The total cost of the tickets for Dea is 6(p - $1.50) dollars.
Since her total cost is $51, we can write the equation:
6(p - $1.50) = $51
To solve this equation, we need to distribute the 6:
6p - 9 = $51
Next, let's isolate the p term by adding 9 to both sides of the equation:
6p = $60
Finally, divide both sides of the equation by 6 to solve for p:
p = $10
Therefore, the regular price of each ticket is $10.
Tickets to the baseball game are on sale for $1.50 off the regular price. Dea buys 6 tickets. If her total cost is $51, what is the regular price of each ticket? Write and solve an equation of the form p(x±q)=r . Then write a sentence to explain your answer
3 answers
can you make that shorter
Sure!
Let's say the regular price of each ticket is p dollars.
Dea buys 6 tickets. The total cost of the tickets without any discount is 6p dollars.
With a discount of $1.50 off the regular price, each ticket costs (p - $1.50).
The total cost for Dea is 6(p - $1.50) dollars.
Since her total cost is $51, we can write the equation: 6(p - $1.50) = $51.
Simplifying, we have 6p - 9 = $51.
Adding 9 to both sides, we get 6p = $60.
Dividing both sides by 6, we find that p = $10.
So, the regular price of each ticket is $10.
Let's say the regular price of each ticket is p dollars.
Dea buys 6 tickets. The total cost of the tickets without any discount is 6p dollars.
With a discount of $1.50 off the regular price, each ticket costs (p - $1.50).
The total cost for Dea is 6(p - $1.50) dollars.
Since her total cost is $51, we can write the equation: 6(p - $1.50) = $51.
Simplifying, we have 6p - 9 = $51.
Adding 9 to both sides, we get 6p = $60.
Dividing both sides by 6, we find that p = $10.
So, the regular price of each ticket is $10.