Question

Given the point (x, y), what is the new point when the point is rotated counterclockwise about the origin 270 degrees

Answer 1

wrong try again

Answer 2

Wrong keep trying

Answer 3

When a point is rotated counterclockwise about the origin, the coordinates of the new point can be found using the following formulas:

new_x = x * cos(theta) - y * sin(theta)
new_y = x * sin(theta) + y * cos(theta)

In this case, since the point is rotated 270 degrees counterclockwise, we can substitute theta with 270 degrees or (3*pi/2) radians.

Thus, the formulas become:

new_x = x * cos(3*pi/2) - y * sin(3*pi/2)
new_y = x * sin(3*pi/2) + y * cos(3*pi/2)

Simplifying further:

new_x = x * 0 - y * (-1)
new_y = x * (-1) + y * 0

which can be simplified as:

new_x = y
new_y = -x

Therefore, the new point is given by (-y, -x).

Answer 4

Apologies for the incorrect response.

If a point (x, y) is rotated counterclockwise about the origin by 270 degrees, the new coordinates can be found using the following formulas:

new_x = x * cos(theta) - y * sin(theta)
new_y = x * sin(theta) + y * cos(theta)

In this case, since the rotation is 270 degrees counterclockwise, we can substitute theta with -270 degrees or (-3*pi/2) radians. This is because a counterclockwise rotation of 270 degrees is equivalent to a clockwise rotation of 90 degrees.

Thus, the formulas become:

new_x = x * cos(-3*pi/2) - y * sin(-3*pi/2)
new_y = x * sin(-3*pi/2) + y * cos(-3*pi/2)

Simplifying further:

new_x = x * cos(-3*pi/2) - y * (-sin(3*pi/2))
new_y = x * (-sin(-3*pi/2)) + y * cos(-3*pi/2)

Using the trigonometric identities cos(-x) = cos(x) and sin(-x) = -sin(x), we can simplify the formulas to:

new_x = x * cos(3*pi/2) + y * sin(3*pi/2)
new_y = -x * sin(3*pi/2) + y * cos(3*pi/2)

Substituting the values of cos(3*pi/2) = 0 and sin(3*pi/2) = -1, we get:

new_x = 0 * x + y * (-1) = -y
new_y = -x * (-1) + y * 0 = x

Therefore, the new point is given by (-y, x).

Answer 5

Apologies for the mistake.

To rotate a point counterclockwise about the origin, we can use the following formulas:

new_x = x * cos(theta) - y * sin(theta)
new_y = x * sin(theta) + y * cos(theta)

In this case, we want to rotate the point (x, y) counterclockwise by 270 degrees. This is equivalent to rotating it by -90 degrees or -pi/2 radians.

We then have:

new_x = x * cos(-pi/2) - y * sin(-pi/2)
new_y = x * sin(-pi/2) + y * cos(-pi/2)

Using the identities cos(-x) = cos(x) and sin(-x) = -sin(x), we simplify to:

new_x = x * cos(pi/2) + y * sin(pi/2)
new_y = -x * sin(pi/2) + y * cos(pi/2)

Since cos(pi/2) = 0 and sin(pi/2) = 1, we have:

new_x = 0 * x + y * 1 = y
new_y = -x * 1 + y * 0 = -x

Therefore, the new point is given by (y, -x).