Question

the the solutions of p(x)=0 and -14 and 11 which function could be p

p(x) = x2 - 3x - 154
p(x) = x2 - 14x + 11
p(x) = x2 + 14x + 11
p(x) = x2 3x - 154

Answer 1

The function that satisfies the solutions p(x) = 0, -14, and 11 is:

p(x) = x^2 - 14x + 11