The noble gas short cut allows us to use the electron configuration of the nearest noble gas that precedes tin, which is xenon (Xe). The electron configuration of xenon is:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶
To determine the electron configuration of tin (Sn), we start by listing the electron configuration of xenon, followed by the additional orbitals for tin. The electron configuration of tin is therefore:
[Xe] 5s² 4d¹⁰ 5p²
Use the noble gas short cut to give the electron configuration of tin. In your answer, put a space between each type of orbital.
1 answer