Question

Quinn and Shawnak are training for a triathlon. They both swim in Birch Lake as a part of their training. One morning, Quinn swam south at a constant velocity for 12.5 minutes. He swam 615 meters in that time. Later that day, Shawnak swam south at a constant velocity for 10.0 minutes. He swam 484 meters in that time. Who swam at a greater velocity, Quinn or Shawnak?

Answer 1

To compare their velocities, we need to find their speeds, which can be calculated by dividing the distance traveled by the time taken.

For Quinn:
Speed = Distance / Time
= 615 meters / 12.5 minutes
= 49.2 meters/minute

For Shawnak:
Speed = Distance / Time
= 484 meters / 10.0 minutes
= 48.4 meters/minute

Quinn swam at a greater velocity than Shawnak.