The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept.
In the given equation, y = -5/3x + 4, the slope is -5/3 and the y-intercept is 4.
To graph the equation, start by plotting the y-intercept at (0, 4). From this point, use the slope of -5/3 to find another point on the line. The slope -5/3 means that for every increase of 3 units to the right, the line decreases by 5 units.
So, starting from (0, 4), as we move 3 units to the right, the line decreases by 5 units. This gives a new point (3, -1). Plot this point on the graph.
Now, draw a straight line connecting the two points (0, 4) and (3, -1). This represents the graph of the linear equation y = -5/3x + 4.
The final graph of the equation y = -5/3x + 4 would show a line that starts at y-intercept (0, 4), and goes downward with a slope of -5/3.
Y=-5/3x+4intercept and slop
Then graph the linear equatio
1 answer
1 answer