When you translate a geometric figure horizontally, in which possible directions might you be moving the figure?
left
up or down
left or right
diagonally right or left
9 answers
When you translate a geometric figure horizontally, you will be moving the figure left or right.
Translate figure PQRS 6 units down and 2 units to the right. What are the coordinates of P′?
(2, 12)
left parenthesis 2 comma 12 right parenthesis
(10, 4)
left parenthesis 10 comma 4 right parenthesis
(6, 0)
left parenthesis 6 comma 0 right parenthesis
(2, 0)
(2, 12)
left parenthesis 2 comma 12 right parenthesis
(10, 4)
left parenthesis 10 comma 4 right parenthesis
(6, 0)
left parenthesis 6 comma 0 right parenthesis
(2, 0)
To translate figure PQRS 6 units down and 2 units to the right, we need to add 6 to the y-coordinate and 2 to the x-coordinate of point P, which is (2, 6).
Adding 6 to the y-coordinate: 6 + 6 = 12
Adding 2 to the x-coordinate: 2 + 2 = 4
Therefore, the coordinates of P' are (4, 12).
The correct answer is: (4, 12) or left parenthesis 4 comma 12 right parenthesis.
Adding 6 to the y-coordinate: 6 + 6 = 12
Adding 2 to the x-coordinate: 2 + 2 = 4
Therefore, the coordinates of P' are (4, 12).
The correct answer is: (4, 12) or left parenthesis 4 comma 12 right parenthesis.
(2, 12)
(10, 4)
(6, 0)
(2, 0)
(10, 4)
(6, 0)
(2, 0)
Apologies for the confusion in my previous response.
To translate point P by moving it 6 units down and 2 units to the right, we need to add 6 to the y-coordinate and 2 to the x-coordinate of point P, which is (2, 0).
Adding 6 to the y-coordinate: 0 + 6 = 6
Adding 2 to the x-coordinate: 2 + 2 = 4
Therefore, the coordinates of P' are (4, 6).
The correct answer is: (4, 6) or left parenthesis 4 comma 6 right parenthesis.
To translate point P by moving it 6 units down and 2 units to the right, we need to add 6 to the y-coordinate and 2 to the x-coordinate of point P, which is (2, 0).
Adding 6 to the y-coordinate: 0 + 6 = 6
Adding 2 to the x-coordinate: 2 + 2 = 4
Therefore, the coordinates of P' are (4, 6).
The correct answer is: (4, 6) or left parenthesis 4 comma 6 right parenthesis.
Translate figure PQRS 6 units down and 2 units to the right. What are the coordinates of P′?
(2, 12)
(10, 4)
(6, 0)
(2, 0)
(2, 12)
(10, 4)
(6, 0)
(2, 0)
To translate figure PQRS 6 units down and 2 units to the right, we need to add 6 to the y-coordinate and 2 to the x-coordinate of point P, which is (2, 0).
Adding 6 to the y-coordinate: 0 + 6 = 6
Adding 2 to the x-coordinate: 2 + 2 = 4
Therefore, the coordinates of P' are (4, 6).
The correct answer is: (4, 6) or left parenthesis 4 comma 6 right parenthesis.
Adding 6 to the y-coordinate: 0 + 6 = 6
Adding 2 to the x-coordinate: 2 + 2 = 4
Therefore, the coordinates of P' are (4, 6).
The correct answer is: (4, 6) or left parenthesis 4 comma 6 right parenthesis.
it's wrong
Apologies for the incorrect response. Let's try the calculation again.
To translate the point P by moving it 6 units down and 2 units to the right, we need to add 6 to the y-coordinate and 2 to the x-coordinate of point P, which is (2, 0).
Adding 6 to the y-coordinate: 0 + 6 = 6
Adding 2 to the x-coordinate: 2 + 2 = 4
Therefore, the coordinates of P' are (4, 6).
The correct answer is: (4, 6).
To translate the point P by moving it 6 units down and 2 units to the right, we need to add 6 to the y-coordinate and 2 to the x-coordinate of point P, which is (2, 0).
Adding 6 to the y-coordinate: 0 + 6 = 6
Adding 2 to the x-coordinate: 2 + 2 = 4
Therefore, the coordinates of P' are (4, 6).
The correct answer is: (4, 6).
1 answer