Asked by unknown
i think i have to simplify.... but the question just says:
(2y-3)^2
possible answers:
a.4y^2+9
b.4y^2-6y+9
c.4y^2-12y+9
d.4y^2+12y+9
(2y-3)^2
possible answers:
a.4y^2+9
b.4y^2-6y+9
c.4y^2-12y+9
d.4y^2+12y+9
Answers
Answered by
~christina~
separate and multiply based on
FOIL
first
outer
inner
last
(2y-3)^2=
(2y-3)(2y-3) then use foil and multiply the first term, outer term, inner terms then last terms .
(2y-3)(2y-3)
first terms multiplied
2y*2y= 4y^2
outer terms multiplied
2y*(-3)=-6y
inner terms multiplied
(-2y)*3=-6y
last terms multiplied
(-3)*(-3)=9
Now combined FOIL (first outer inner and last terms )
4y^2-6y-6y+9= but now you can combine the -6y's so (-6y-6y=-12y)
and you get 4y^2-12y+9
FOIL
first
outer
inner
last
(2y-3)^2=
(2y-3)(2y-3) then use foil and multiply the first term, outer term, inner terms then last terms .
(2y-3)(2y-3)
first terms multiplied
2y*2y= 4y^2
outer terms multiplied
2y*(-3)=-6y
inner terms multiplied
(-2y)*3=-6y
last terms multiplied
(-3)*(-3)=9
Now combined FOIL (first outer inner and last terms )
4y^2-6y-6y+9= but now you can combine the -6y's so (-6y-6y=-12y)
and you get 4y^2-12y+9
Answered by
DrBob222
duplicate post
Answered by
~christina~
inner terms multiplied
2y*<b>(-3)</b>=-6y
it is the same as the outer terms multiplied (the negative was misplaced before)
Answered by
~christina~
Oh..it was a duplicate?
Oh well I solved it Dr.Bob.=D
anyways..ha
Oh well I solved it Dr.Bob.=D
anyways..ha
Answered by
unknown
thank you...
Answered by
~christina~
Your welcome =)
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