Question

suppose a polar bear running with an initial speed of 4.0 m/s accelerates uniformly for 18s. what is the bear's maximum speed if the bear travels 135m during the 18s of acceleration? Give the answer in both meters per second and kilometers per hour.

Answer 1

distane=vi*time+ 1/2 aT^2
distance=4*18+ a*18^2 solve for a.
Then..
Vf=Vi + a*t