Asked by unknown
i think i have to simplify.... but the question just says:
(2y-3)^2
a.4y^2+9
b.4y^2-6y+9
c.4y^2-12y+9
d.4y^2+12y+9
i got A but i wanna make sure....
(2y-3)^2
a.4y^2+9
b.4y^2-6y+9
c.4y^2-12y+9
d.4y^2+12y+9
i got A but i wanna make sure....
Answers
Answered by
Mr. Kim
yes... A. is the correct answer.
Answered by
DrBob222
Just expand the binomial.
You know how to do it?
First term is (2y)^2 = 4y^2.
Second term is twice the product inside the parentheses which is 2y*-3 = -6y and twice that is -12y.
The third term is the last number squared which is -3<sup>2</sup> or +9. Do you see any answers that fit that? I do. If you will learn the method I showed you, you can do these things in your head.
You know how to do it?
First term is (2y)^2 = 4y^2.
Second term is twice the product inside the parentheses which is 2y*-3 = -6y and twice that is -12y.
The third term is the last number squared which is -3<sup>2</sup> or +9. Do you see any answers that fit that? I do. If you will learn the method I showed you, you can do these things in your head.
Answered by
DrBob222
A point of clarification: A is not the correct answer.
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