First, let's solve the second equation for x:
3x = 15
Divide both sides by 3:
x = 5
Now we can substitute this value of x into the first equation:
4(5) + 5y = 40
20 + 5y = 40
Subtract 20 from both sides:
5y = 20
Now divide both sides by 5:
y = 4
So the solutions to the system of equations are x = 5 and y = 4.
Solve. 4x+5y=40 3x=15
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