The given sequence is an arithmetic sequence with a common difference of 3. To find the sum of the first 16 terms, we can use the formula for the sum of an arithmetic sequence:
Sn = (n/2)(2a + (n-1)d)
where Sn is the sum of the first n terms, a is the first term, and d is the common difference.
Plugging in the given values, we have:
Sn = (16/2)(2(2) + (16-1)(3))
= 8(4 + 15(3))
= 8(4 + 45)
= 8(49)
= 392
Therefore, the sum of the first 16 terms of the sequence is 392.
Q2. The sum of the first 16 terms of the sequence: 2,5,8,11,14,.........s
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