If minus, 5, x, plus, 4, y, equals, minus, 3−5x+4y=−3 is a true equation, what would be the value of minus, 6, left bracket, minus, 5, x, plus, 4, y, right bracket−6(−5x+4y)?

Answer 1

To find the value of "-6(-5x+4y)" if the equation is true, we need to substitute the values of x and y from the given equation.

Given: -3 - 5x + 4y = -3

We can see that "-3" is canceled out from both sides.

So, -5x + 4y = 0

Now substitute this equation back into the expression -6(-5x+4y):

-6(-5x+4y) = -6(0) = 0

Therefore, the value of -6(-5x+4y) is 0.