Evaluate2x+x+3y+6%0D%0A2%0D%0A%0D%0A+%0D%0A%0D%0A+%0D%0A3%0D%0A%0D%0A+%0D%0A6%0D%0A when x=3 and y=10%0D%0A%0D%0A=%0D%0A3%0D%0A %0D%0A%0D%0A%0D%0A%0D%0A %0D%0A%0D%0A=%0D%0A10%0D%0A(1 point)%0D%0AResponses%0D%0A%0D%0A45%0D%0A45%0D%0A%0D%0A27%0D%0A27%0D%0A%0D%0A342%0D%0A342%0D%0A%0D%0A39

1 answer

To evaluate the expression, we substitute the given values of x=3 and y=10 into the expression:

2x + x + 3y + 6
= 2(3) + 3 + 3(10) + 6
= 6 + 3 + 30 + 6
= 45

Therefore, the value of the expression is 45 when x=3 and y=10.