The vertex of a quadratic can be found using the formula:
x = -b / 2a
In the given quadratic y = 4x^2 + 3x - 8, a = 4 and b = 3.
Therefore,
x = -3 / (2 * 4) = -3 / 8
Plugging this value in the equation, we can find the y-coordinate of the vertex:
y = 4(-3/8)^2 + 3(-3/8) - 8 = -29/8
So, the vertex of the quadratic is (-3/8, -29/8).
The graph of the quadratic is a parabola that opens upwards. It looks something like this:
{{{graph(400,400,-5,5,-10,10,4x^2+3x-8)}}}
Graph the quadratic y=4x^2+3x−8. What is the vertex of this quadratic?
1 answer