Asked by Anonymous

Suppose a piece of lead with a mass of 14.9 g at a temperature of 92.5 C is dropped into an insulated container of water. The mass of water is 165 g and its temperature before adding the lead is 20.0 C. What is the final temperature?

I know that I have to multiply (mass in grams)(change in temperature)(specific heat) but I think I'm missing a step because I can't find the anwer to the problem.
Answered by DrBob222
heat lost by lead + heat gained by water = 0

masslead*specific heat lead * (Tf - Ti) + mass H2O * specific heat water * (Tf - Ti) = 0
Tf is final T
Ti is initial T.
solve for Tf. Post your work if you get stuck.
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