Asked by lina
Your spaceship lands on an unknown planet. To determine the local value of g, you ask a steel-toed crew member to kick a stone, and you find that if she kicks it at 18.0m/s at various angles, the maximum range she can achieve is 30.8m.
What is g on this planet?
How long was the stone in the air?
How high above the ground did the stone go?
What is g on this planet?
How long was the stone in the air?
How high above the ground did the stone go?
Answers
Answered by
bobpursley
Ok, you already know that an angle of 45 deg gives the max range.
In the vertical:
hf=hi+18sin45t-1/2 g t^2
but hi=hf so
t= 2*18sin45/g
in the horizontal
30.8=18cos45*t put t in and solve for g.
In the vertical:
hf=hi+18sin45t-1/2 g t^2
but hi=hf so
t= 2*18sin45/g
in the horizontal
30.8=18cos45*t put t in and solve for g.
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