Asked by Brit
Show that gh(-2)= 14 g(x) 2x+1/x-1 and h(x) 4x+3/x-2
Is it 2(4x+3/x-2)/x-1 and i work from there?
Is it 2(4x+3/x-2)/x-1 and i work from there?
Answers
Answered by
bobpursley
if g(x)=(2x+1)/(x-1)
and h(x)=(4x+3)/(x-2)
then
g(h(-2))=g(-5/-4)=g(5/4)
g(5/4)=(10/4+1)/(-1/4)=-14 if I didn't make a mistake, check me.
and h(x)=(4x+3)/(x-2)
then
g(h(-2))=g(-5/-4)=g(5/4)
g(5/4)=(10/4+1)/(-1/4)=-14 if I didn't make a mistake, check me.
Answered by
Reiny
I will assume that by gh(-2) you mean
g(f(-2))
first do f(-2)
= -5/-4 = 5/4
now do g(5/4) = (5/2 + 1)/(5/4 - 1)
= (7/2)/(1/4)
= (7/2)(4/1)
= 14
g(f(-2))
first do f(-2)
= -5/-4 = 5/4
now do g(5/4) = (5/2 + 1)/(5/4 - 1)
= (7/2)/(1/4)
= (7/2)(4/1)
= 14
Answered by
bobpursley
I agree with Reiny on the +14.
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