x+5+2*(-1)[(x^1+x^2=2(-1)]

Question

y+2=2*0[y^1+y^2=2*0]
simplify

Answer 1

To simplify the expression, let's start by evaluating the expressions within the brackets separately:

For the first term:
(x^1 + x^2) = x + x^2

For the second term:
2(-1) = -2

Now, substituting these values back into the original expression:

x + 5 + 2(-1)[(x^1 + x^2) = 2(-1)]

x + 5 + 2(-1)[x + x^2 = -2]

x + 5 + 2x + 2x^2 = -4

3x + 2x^2 + 5 = -4

Rearranging the terms:

2x^2 + 3x + 9 = 0

Now, let's simplify the second expression:

y + 2 = 2 * 0[y^1 + y^2 = 2 * 0]

y + 2 = 0

To solve for y, subtract 2 from both sides:

y = -2

So, the simplified expressions are:

For x: 2x^2 + 3x + 9 = 0

For y: y = -2