Question

Three forces acting on an object are given by F1 = (-8.79i + 8.34j) N, F2 = (7.06i + -3.02j) N, and F3 = (-3.05i) N. The object experiences an acceleration of magnitude 2.26 m/s2. What are the components of the acceleration vector?

Answer 1

The net force is -4.78i +5.22j. Its magnitude is
{F} = sqrt[(-4.78)^2 + 5.22^2] = 7.08 N. The mass is therefore
|F|/a = 3.13 kg

For the acceleration vector, divide the force vector by the mass.

Answer 2

thanks a lot. that really helped.