Asked by Kat
Person X travels from A to B and then back the same route at a constant speed of 50 km/h. Person Y travels the same route to B at half the speed. How fast does person Y have to travel back to make the complete return trip in the same time as person X?
Answers
Answered by
drwls
Let V be the speed of person X (50 km/h) and D be the distance travelled, one-way. Let the unkvown return speed of person Y be V'.
2D/V = D/(V/2) + D/V'
D/V' = 0
V' = infinite
By the time Y reaches the turnaround point, X has already completed the round trip. Y cannot catch up.
2D/V = D/(V/2) + D/V'
D/V' = 0
V' = infinite
By the time Y reaches the turnaround point, X has already completed the round trip. Y cannot catch up.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.