Two mangos cost as much as five oranges. Mr. Lim bought 3 mangos and five oranges for $25. How much should Mr. Lim pay if he bought 9 mangos?

Answer 1

Let x be the cost of one mango.
Therefore, the cost of 3 mangos is 3x.
The cost of 5 oranges is 5*x/2 = 5x/2.
The total cost of 3 mangos and 5 oranges is 3x + 5x/2 = $25.
Combining like terms, we get 6x/2 + 5x/2 = $25.
Combining the fractions, we get 11x/2 = $25.
Multiplying both sides of the equation by 2/11, we get x = $25 * 2/11 = $4.55.
Therefore, the cost of one mango is $4.55.
If Mr. Lim bought 9 mangos, he needs to pay 9*$4.55 = $<<9*4.55=40.95>>40.95. Answer: \boxed{40.95}.