Asked by lamiya
Simplify the expressions.
1. (-6c^2)(2c^2-3c)
2. (-5d-10d^2)(-6d^3)
3. x^3-(4x+3x^2)(x^2)
4. (-8y^2)(3y-4)+6y^2-5y^3
5. (18m/-4n) / (-1/4m)
6. (5x^2) / (2x/15)
7. (-16x+9) / (-4)
8. (-32-4x) / (-8)
I don't get how to do these. Please help!! Thanks a lot!! =)
1. (-6c^2)(2c^2-3c)
2. (-5d-10d^2)(-6d^3)
3. x^3-(4x+3x^2)(x^2)
4. (-8y^2)(3y-4)+6y^2-5y^3
5. (18m/-4n) / (-1/4m)
6. (5x^2) / (2x/15)
7. (-16x+9) / (-4)
8. (-32-4x) / (-8)
I don't get how to do these. Please help!! Thanks a lot!! =)
Answers
Answered by
MathMate
First you have to study the laws of exponents, which include:
a<sup>x</sup> * a<sup>y</sup> = a<sup>x+y</sup>
a<sup>x</sup> / a<sup>y</sup> = a<sup>x-y</sup>
a<sup>x</sup> * a<sup>y</sup> = (a<sup>x+y</sup>)<sup>y</sup> = a<sup>xy</sup>
a<sup>-x</sup> = 1/a<sup>x</sup>
a<sup>1/x</sup> = xth root of a
When you have a multiplication of powers, you would group together factors with the same base and apply the above rules.
I will do the first one to give you a kick-start.
(-6c^2)(2c^2-3c)
= -6 (c²)(2c²-3c)
= -6 (2c<sup>2+2</sup> - 3c<sup>2+1</sup>)
= -6(2c⁴-3c³)
= -12c⁴+18c³)
a<sup>x</sup> * a<sup>y</sup> = a<sup>x+y</sup>
a<sup>x</sup> / a<sup>y</sup> = a<sup>x-y</sup>
a<sup>x</sup> * a<sup>y</sup> = (a<sup>x+y</sup>)<sup>y</sup> = a<sup>xy</sup>
a<sup>-x</sup> = 1/a<sup>x</sup>
a<sup>1/x</sup> = xth root of a
When you have a multiplication of powers, you would group together factors with the same base and apply the above rules.
I will do the first one to give you a kick-start.
(-6c^2)(2c^2-3c)
= -6 (c²)(2c²-3c)
= -6 (2c<sup>2+2</sup> - 3c<sup>2+1</sup>)
= -6(2c⁴-3c³)
= -12c⁴+18c³)
Answered by
MathMate
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