A tennis ball is dropped from 1.41m above the ground. It rebounds to a height of 0.932 m.The acceleration of gravity is 9.8 m/s2 .(a)With what velocity does it hit the ground?(Let down be negative.) Answer in units of m/s. (b)With what velocity does it leave the ground? Answer in units of m/s. (c)If the tennis ball were in contact with the ground for 0.00575 s, find the acceleration given to the tennis ball by the ground. Answer in units of m/s2.

Answer 1

(c)
Force = rate of change of momentum.
Calculate the momentum change, divide by the contact duration, you will get the acceleration, after the mass cancels out.
It will be a huge number over 1600 m/s/s.
See also following link for your reading:
http://www.vias.org/physics/example_2_5_13.html

Answer 2

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Answer 3

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Answer 4

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