acceleartiononmoon= GMassmoon/radius^2
=G 7.35E22/(1.74E6)^2= G 2.43E10=
= 6.67E-11*2.43E10=
1.62 m/s^2 or as a gravitational field constant= 1.62 N/kg
I have no idea why you used the mass of Earth.
Calculate the acceleration due to gravity on the moon. The moon\'s radius is about 1.74 E 6 m and its mass is 7.35 E 22 kg
ok aparently there\'s an easier way to do this
I applied Newtons second law in the radial direction
net force radial = m (radial acceleration) = Fg
were Fg is r^-2 G m m2
I solved for the period then calculated the acceleration to be
5.91 E 18 s^-3 m
how do I do this because I just assumed that it was the Earth\'s moon which... isn\'t necissarily true and i used the mass of the earth which wasn\'t given in the problem i used 5.98 E 24 kg for mass of earth
what is the easy way to do this...
my teacher told me
Little g is the force of gravity (weight) divided by the mass of the object that’s feeling the force. Another way to look at it: little g helps find the force a single kilogram of mass would feel. It describes the force per unit mass. You could say that g = W/m (which makes sense, when you consider that W = mg).
not exactly sure what the heck it\'s talking about because Fg or in that case weight is not equal to mg
1 answer
1 answer