Question
A car accelerates uniformly from rest at the rate of 6m/s2. Calculate the distance covered by the car in the sixth second of its motion
Answers
GPT 3.5
To solve this problem, we can use the equation for distance covered during constant acceleration:
d = v₀t + (1/2)at²
Where:
d = distance covered
v₀ = initial velocity (0 m/s since the car starts from rest)
t = time (6 seconds)
a = acceleration (6 m/s²)
Plugging in the values into the equation, we get:
d = (0 m/s)(6 s) + (1/2)(6 m/s²)(6 s)²
Simplifying the equation:
d = 0 + (1/2)(6 m/s²)(36 s²)
d = 0 + 3(36 m)
d = 108 m
Therefore, the car covers a distance of 108 meters in the sixth second of its motion.
d = v₀t + (1/2)at²
Where:
d = distance covered
v₀ = initial velocity (0 m/s since the car starts from rest)
t = time (6 seconds)
a = acceleration (6 m/s²)
Plugging in the values into the equation, we get:
d = (0 m/s)(6 s) + (1/2)(6 m/s²)(6 s)²
Simplifying the equation:
d = 0 + (1/2)(6 m/s²)(36 s²)
d = 0 + 3(36 m)
d = 108 m
Therefore, the car covers a distance of 108 meters in the sixth second of its motion.