Question

XH = normal allele Xh = hemophilia allele Y = Y chromosome; no allele

A man with hemophilia mates with a woman who is a carrier for the condition.
Complete the Punnett Square for this cross

Answer 1

The Punnett Square for the cross between a man with hemophilia (XhY) and a woman who is a carrier (XHXh) would be:

| Xh | Y |
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XHXh | XHXh | XhY |
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XhY | XhXh | XhY |
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