Question
Calculate the mass of ammonium nitrate that would contain 14g of nitrogen
Answers
Answered by
GPT 3.5
The molar mass of ammonium nitrate (NH4NO3) can be calculated by summing the molar masses of its components:
Molar mass of nitrogen (N) = 14.01 g/mol
Molar mass of hydrogen (H) = 1.01 g/mol
Molar mass of oxygen (O) = 16.00 g/mol
Molar mass of ammonium nitrate (NH4NO3) = (1 * molar mass of nitrogen) + (4 * molar mass of hydrogen) + (3 * molar mass of oxygen)
= (1 * 14.01 g/mol) + (4 * 1.01 g/mol) + (3 * 16.00 g/mol)
= 28.04 g/mol + 4.04 g/mol + 48.00 g/mol
= 80.08 g/mol
To find the mass of ammonium nitrate containing 14 g of nitrogen, we can use the molar mass of ammonium nitrate calculated above:
Mass of ammonium nitrate = (Mass of nitrogen / Molar mass of nitrogen) * Molar mass of ammonium nitrate
= (14 g / 14.01 g/mol) * 80.08 g/mol
≈ 79.94 g
Therefore, the mass of ammonium nitrate that would contain 14 g of nitrogen is approximately 79.94 grams.
Molar mass of nitrogen (N) = 14.01 g/mol
Molar mass of hydrogen (H) = 1.01 g/mol
Molar mass of oxygen (O) = 16.00 g/mol
Molar mass of ammonium nitrate (NH4NO3) = (1 * molar mass of nitrogen) + (4 * molar mass of hydrogen) + (3 * molar mass of oxygen)
= (1 * 14.01 g/mol) + (4 * 1.01 g/mol) + (3 * 16.00 g/mol)
= 28.04 g/mol + 4.04 g/mol + 48.00 g/mol
= 80.08 g/mol
To find the mass of ammonium nitrate containing 14 g of nitrogen, we can use the molar mass of ammonium nitrate calculated above:
Mass of ammonium nitrate = (Mass of nitrogen / Molar mass of nitrogen) * Molar mass of ammonium nitrate
= (14 g / 14.01 g/mol) * 80.08 g/mol
≈ 79.94 g
Therefore, the mass of ammonium nitrate that would contain 14 g of nitrogen is approximately 79.94 grams.