Question
A 10000 N car comes to a bridge during a storm and finds the bridge washed out. The 750 N driver must get to the other side, so he decides to try leaping it with his car. The side the car is on is 21.6 m above the river, while the opposite side is a mere 3.60 m above the river. The river itself is a raging torrent 63.0 m wide.
How fast should the car be traveling just as it leaves the cliff in order to clear the river and land safely on the opposite side?
got it....33 m/s
What is the speed of the car just before it lands safely on the other side?
yeah...don't know...not even a little bit
What is the speed of the car? The easy way is to use Energy..
He started with 1/2 m v^2 (and you figured v) plus mgh of Potential energy (h=21.6-3.6). Add those. Then when he landed, he had 1/2 m v^2 of energy, so calcuate v.
The other way is you know the initial horizontal velocity, that is also the final horizontal velocity. The vertical velocity at impact will be v= sqrt(2gh).Add those two velocities as vectors.
How fast should the car be traveling just as it leaves the cliff in order to clear the river and land safely on the opposite side?
got it....33 m/s
What is the speed of the car just before it lands safely on the other side?
yeah...don't know...not even a little bit
What is the speed of the car? The easy way is to use Energy..
He started with 1/2 m v^2 (and you figured v) plus mgh of Potential energy (h=21.6-3.6). Add those. Then when he landed, he had 1/2 m v^2 of energy, so calcuate v.
The other way is you know the initial horizontal velocity, that is also the final horizontal velocity. The vertical velocity at impact will be v= sqrt(2gh).Add those two velocities as vectors.