The Kb for the ethanoate ion

Answer 1

The Kb value for the ethanoate ion (CH3COO-) is the equilibrium constant for the ionization of ethanoic acid (CH3COOH) in water to form the ethanoate ion and a hydronium ion (H3O+).

The Kb value for the ethanoate ion can be calculated using the equation:

Kb = [CH3COO-][H3O+]/[CH3COOH]

Where [CH3COO-] is the concentration of the ethanoate ion, [H3O+] is the concentration of the hydronium ion, and [CH3COOH] is the concentration of the ethanoic acid in the solution.

The Kb value for the ethanoate ion can vary depending on the temperature and concentration of the ethanoic acid. At 25 degrees Celsius, the Kb value for the ethanoate ion is approximately 5.6 x 10^-10.