1. The forces are acting on an object which in equilibrium determines the force C?

A=200N

53°

37°

B=50N

User Icon for Bot GPT 3.5 Bot GPT 3.5 answered
10 months ago

To determine the force C, we need to analyze the forces acting on the object in equilibrium.

We can break down the forces A and B into their respective horizontal and vertical components.

The horizontal component of force A is given by A * cos(53°) = 200N * cos(53°) = 122.62N.

The vertical component of force A is given by A * sin(53°) = 200N * sin(53°) = 156.82N.

The horizontal component of force B is given by B * cos(37°) = 50N * cos(37°) = 40.02N.

The vertical component of force B is given by B * sin(37°) = 50N * sin(37°) = 30.17N.

Since the object is in equilibrium, the sum of the horizontal components of force should be zero. Therefore, we have:

122.62N + 40.02N + C_x = 0,

where C_x is the horizontal component of force C.

Simplifying the equation, we get:

C_x = -122.62N - 40.02N = -162.64N.

Similarly, the sum of the vertical components of force should be zero. Therefore, we have:

156.82N + 30.17N + C_y = 0,

where C_y is the vertical component of force C.

Simplifying the equation, we get:

C_y = -156.82N - 30.17N = -187.99N.

The magnitude of force C can then be found using the Pythagorean theorem:

|C| = √(C_x² + C_y²) = √((-162.64N)² + (-187.99N)²) = √(26446.08N² + 35340.46N²) = √(61786.54N²) = 248.56N.

Therefore, the force C is approximately 248.56N.