To calculate the net force acting on the toy helicopter, we need to consider the forces acting in the vertical and horizontal directions separately.
In the vertical direction:
- The force of gravity pulls the helicopter down with a force of 5 N.
- The propeller provides an upward force of 10 N.
Hence, the net vertical force is:
Net vertical force = Upward force (propeller) - Downward force (gravity)
= 10 N - 5 N
= 5 N (upward)
In the horizontal direction:
- The helicopter flies forward with a force of 15 N.
- The oncoming wind provides a force of 10 N in the opposite direction.
Hence, the net horizontal force is:
Net horizontal force = Forward force - Opposing force (wind)
= 15 N - 10 N
= 5 N (forward)
Therefore, the net force acting on the toy helicopter can be determined by calculating the vector sum of the vertical and horizontal forces:
Net force = √[(Net vertical force)^2 + (Net horizontal force)^2]
= √[(5)^2 + (5)^2]
= √[25 + 25]
= √50
≈ 7.07 N
Thus, the net force acting on the toy helicopter is approximately 7.07 N.
a toy helicopter flies forward with the force of 15 n into an oncoming wind of 10n the force of gravity pulls helicopter down with a force of 5 n but the propeller is providing an upward force 10n
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