if ABC is a right angled triangle , sin(A) = 3/5 , then sin(B+c)

Answer 1

To find sin(B+C), we first need to find angles B and C.

Since ABC is a right-angled triangle, we know that A + B + C = 90 degrees.

Since A is the right angle, A = 90 degrees.

Therefore, B + C = 90 - A = 90 - 90 = 0 degrees.

However, sin(0 degrees) = 0, so sin(B+C) = 0.