if ABC is a right angled triangle , sin(A) = 3/5 , then sin(B+c+

Answer 1

Assuming that B and C are the acute angles in the right-angled triangle ABC, we can use the fact that the sum of angles in a triangle is 180 degrees.

Since A is the right angle, B + C = 90 degrees.

Given that sin(A) = 3/5, we know that sin(A) = sin(90) = 1.

Using the sine addition formula, sin(B+C) = sin(B)cos(C) + cos(B)sin(C).

Since B + C = 90, we have sin(B+C) = sin(90) = 1.

Thus, sin(B+C) = 1.