Ann Marie tried on 6 dresses from her closet for her dance and left 4/7

Question

of them on hangers because she got tired. How many dresses were originally in her closet?

Answer 1

Let's assume that x represents the number of dresses originally in Ann Marie's closet.

According to the problem, she left 4/7 of the dresses on hangers, which means she had 4/7 * x dresses left.

Since she tried on 6 dresses, she had 4/7 * x - 6 dresses left.

We know that she left this amount because she got tired, so the equation becomes: 4/7 * x - 6 = 0.

To solve for x, we can add 6 to both sides of the equation: 4/7 * x = 6.

Next, we can multiply both sides of the equation by 7/4: x = 6 * 7/4 = 42/4 = 10.5.

Since you can't have a fraction of a dress, the original number of dresses in her closet must be a whole number. Therefore, Ann Marie originally had 10 dresses in her closet. Answer: \boxed{10}.