the freshman class ranges in height from 4'8"-6'. Write a compound inequality for the height of a freshman "f". Then write it as an absolut value inequality.
2 answers
Hmm. I think I know the compound. Isn't that just 4'8" is less than or equal to 'F' is less then or equal to 6'?
4'8" ≤ f ≤ 6'
An absolute value is the distance from zero.
By translating the zero to the middle of the range of heights, the above inequality can be transformed into one with only one inequality sign using absolute value.
Average of range
=(4'8" + 6')/2 = 5'4"
Half of range
=(6'-4'8")/2= 8"
The absolute value inequality
= |f-5'4"| ≤ 8"
An absolute value is the distance from zero.
By translating the zero to the middle of the range of heights, the above inequality can be transformed into one with only one inequality sign using absolute value.
Average of range
=(4'8" + 6')/2 = 5'4"
Half of range
=(6'-4'8")/2= 8"
The absolute value inequality
= |f-5'4"| ≤ 8"
3 answers